Monthly Archives: November 2008

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Important Equations Everyone Must Know But Never Taught In School

This equation should be taught in all A-Math and E-math classes! (But never taught in school)

From a strictly mathematical viewpoint it goes like this:

What Makes 100%?

What does it mean to give MORE than 100%?

Ever wonder about those people who say they are giving more than 100%?

We have all been to those meetings where someone wants you to give over 100%.

How about achieving 103%? What makes up 100% ! in life?

Here’s a little mathematical formula that might help you answer these questions:

If:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z is represented as:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26.

Then:

H-A-R-D-W-O-R-K
8+1+18+4+23+15+18+11 = 98% !

and
K-N-O-W-L-E-D-G-E
11+14+15+23+12+5+4+7+5 = 96%

But,

A-T-T-I-T-U-D-E
1+20+20+9+20+21+4+5 = 100%

So, one can conclude with mathematical certainty that While Hard work and Knowledge will get you close, and Attitude will get you there.

Email courtesy of Nzm

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My First Handwritten Blogpost using My Tablet PC

With this technology, you will receive more A-Math and E-Math ‘s Exam Questions, Tips and Strategies.

Stay Tuned!

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How To Solve “Clones” Type Of Logarithm Equations

In the previous post, I shared with you on the main Types of Logarithm Equations and How To Identify Them Easily.

Today, I’m going to share with you the step by step approach to solve Clone! type of Logarithm Equations.

Photo by Chris Gin

Clone Dolly

The strategy involving

  • identifying the clone which is relatively easy since clones are items which look EXACTLY the same.
  • Let the clone by y (Substitution method)

(log_5 x)^2 = 2log_5 x

Let log_5 x be y

Substitution:

y^2 = 2y

Common Mistake! (Canceling y from each side of the equation; So What? : you will miss out 1 answer)

y = 2

Correct Approach (Shift everything to left hand side so that right hand side is 0; So What? :Ready for factorization since it is a quadratic equation)

y^2 - 2y = 0

y(y - 2) = 0

y = 0  or y - 2 = 0

Remember we are interested in the unknown in the question (x) NOT y!

log_5 x = 0  or log_5 x = 2

x = 1  or x = 25

Check validity of answers by substituting values of x into the original given equation. Both values are acceptable.

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