Another question for O Level Additional Mathematics (A-Math).
On the same diagram, sketch the graphs of
y=sin 3x & y=cos2x,
for x between 0 degree and 180 degree
Hence state the number of soutions to the equation
sin 3x=cos 2x
in the interval 0 degree less than or equals to x which is less then or equals to 180 degree
Click on image to have a larger view
Another question from O Level Additional Mathematics (A-Math).
If p =( 1 + cosx )/sinx, 1/p= ( 1 – cosx )/( sinx ), find sinx and cosx in terms of p.
first of all, we would love to thanks all those who have posted your comments, shared your thoughts, asked your questions :)
Keep them coming! we welcome all! Since O Level is coming by in 25 days time, we would love to continue to see this blog active. btw, did i mention that there are on average 100 of you viewing this blog daily? not a huge number but both me and sean are happy that there are people who visit this blog. and we will continue to provide you with tips to do well.
well, to ensure that you gain the most of out this, you yourself must participate! yeah participate is the key! ask all sorts of qns, answer qns the way u think is correct, just do it anyway! it is through participation that we can truly experience and learn at the maximum potential.
so when there are qns, have a pen and paper and work things out! see if your concepts and understanding are firm and clear.
keep the fire burning!
Cheers!
Another question from O Level Additional Mathematics (A-Math).
How many even 5-digit numbers more than 50000 can be formed using the digits, 1,2,3,4,5,6,7 if no digit is to be repeated?
Conditions
#1: Even
#2: 5-digit number
#3: no digit is to be repeated
Case 1:When the first digit is odd (must be more than or equal to 5)
2C1 * 5P3 * 3C1
Logic & Reasoning:
first digit: either 5 or 7 so 2C1
last digit: either 2,4 or 6 so 3C1
the remaining 3 digits can be choosen from the leftover 5 numbers so 5C1*4C1*3C1 also = 5P3Case 2:When the first digit is even
5P3 * 2C1
Logic & Reasoning:
first digit: 6 so no need to choose just put!
last digit: either 2 or 4 so 2C1
the remaining 3 digits can be choosen from the leftover 5 numbers so 5C1*4C1*3C1 also = 5P3Total even 5-digit numbers more than 50000 can be formed using the digits, 1,2,3,4,5,6,7 if no digit is to be repeated = Case 1 + Case 2 = 480
:)
Hi,
I'm Ai Ling. I enjoy coaching students who have challenges with
understanding and scoring in 'O' Level A-Maths and E-Maths. 
