This is an interesting question which I came across under Additional Mathematics (A-Math):
Find the value of x.
Who is courageous to work on this question?
I will respond to this question when someone discusses about this question first :)
Update:
(Apply Power Law)
(multiply by 4 on both sides of equal sign)
(Apply Power Law)
(Apply Quotient Law)
(Factorise)
(log-baseX-root3)(log-baseX-root8)=1.5(log-baseX-1/root2)
(0.5log-baseX-3)(1.5log-baseX-2)=1.5(log-baseX-2^-0.5)
[cancel 1.5 from both sides]
(0.5log-baseX-3)(log-baseX-2)= -0.5(log-baseX-2)
[cancel 0.5 from both sides]
(log-baseX-3)(log-baseX-2) + (log-baseX-2)= 0
(log-baseX-2) (log-baseX-3 + 1) = 0
therefore,
(log-baseX-2)=0 or (log-baseX-3 + 1)=0
X^0= 2 (rejected) (log-baseX-3)= -1
X^(-1) = 3
thus X= 1/3
hope i didnt make any mistakes
Logarithm rocks! XDD
awesome!
Tks for the effort.
This question is fun. Perhaps, you will like to let your students to try to solve the question.
Solve the equation
(2/x)^(log n 4) - (3/x)^(log n 9) = 0
Regards,
ahm97sic
This is another interesting question. Perhaps, you will like to let your students to try to solve the question.
Solve (log a X)^(log b X) = X
where a, b are positive real numbers except 1, leave
the answer in terms of a and b.
Regards,
ahm97sic
Hie you are just an amazing lady thanks for everything.i will chat with you next time,tell me about your place the temperature & the environment