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Logarithm Equation Question 2 [Checking validity of answers in logarithms equations]


Solve the equation

\lg(3a+2)+ lg(5a-3)=1+ 2lg (a)

Ans : a = 1 or -6/5

Question : Do we need to include -6/5

Contributed by YC

It is important for you to check if your answers are valid i.e are there any answers you would need to reject?
This is what I called checking for validity of answers.

Ai Ling Ong

Hi, I'm Ai Ling Ong. I enjoy coaching students who have challenges with understanding and scoring in 'O' Level A-Maths and E-Maths. I develop Math strategies, sometimes ridiculous ideas to help students in understanding abstract concepts the fast and memorable way. I write this blog to share with you the stuff I teach in my class, the common mistakes my students made, the 'way' to think, analyze... If you have found this blog post useful, please share it with your friends. I will really appreciate it! :)

Filed Under: A-Maths Tuition, Weekly Question Tagged With: logarithm equations, validity of answers

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Comments

  1. Humairah says

    March 27, 2008 at 12:03 am

    I guess, we do not include -6/5 as there is no such graph of log(-a).

  2. alwaysLovely says

    March 28, 2008 at 11:09 am

    Good answer. Absolutely correct!
    Continue to participate!

  3. Algebra says

    December 5, 2008 at 2:45 pm

    Clearly the domain (admissible values of x for the argument of the function f(x)=lg(x)) of f(x) is (0, \infty). If a=-6/5, then 3a+2 is negative; therefore x=-6/5 is not admissible into the domain of function f(x).

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