In this post, we are going to discuss on the applications of vectors -** Finding Ratio of Areas**. This is a popular section in examinations and based on my many years of experience, students simply don't like it due to many of them disliking and not making sense of the topic on Similar Triangles.

**Strategy #1 : Similar Triangles**

In Similar Triangles, the ratio of 2 similar triangles can be easily found by **squaring the ratio of their corresponding length.**

[pmath]({A_1}/{A_2})=({l_1}/{l_2})^2[/pmath]

**Strategy #2 : Common Base/Common Height**

I am going to use this examination question below to illustrate the application of Strategy #2. This strategy works when the triangles shared either a common base or a common height. And that the triangles are not similar.

Watch the video below to find out if your answers are correct. Included in this video is a trick which will help you to 'see' your answer faster!

**Rate the video or leave me a comment or question.**

**Strategy #3 : Overlap**

When strategy 1 or 2 do not work and the question involves repeated triangles, overlap is the strategy you can apply. Overlap involves **equalizing of ratio of THE triangle which overlaps.**