Video Solution Of Plane Geometry Question (Plus:Strategy To Handle Angles)

This is the step by step video solution for this Plane Geometry question

Inside this video, you will get to know how I begin this question with a clear objective and the steps I took to achieve this objective.

I used 2 strategies (on differentiating the angles) to quickly and easily prove this question.

• Letting an angle be x
• Usage of color (In exams, you can perhaps use different type of lines to differentiate the angles as well)

Hear from you on this approach. If you have your own approach, we would love to hear from you.

Leave me a comment in the section below.

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Ai Ling Ong

Hi, I'm Ai Ling Ong. I enjoy coaching students who have challenges with understanding and scoring in 'O' Level A-Maths and E-Maths. I develop Math strategies, sometimes ridiculous ideas to help students in understanding abstract concepts the fast and memorable way. I write this blog to share with you the stuff I teach in my class, the common mistakes my students made, the 'way' to think, analyze... If you have found this blog post useful, please share it with your friends. I will really appreciate it! :)

5 Responses to Video Solution Of Plane Geometry Question (Plus:Strategy To Handle Angles)

1. Thanks for sharing with us the answers!

I was looking at this question for some time but dont seems to be able to find a way to prove it!

I hate proving questions in Mathematics.
Your step-by-step solutions certainly helped me to have a clearer picture of the strategy to use.

Keep sharing more with us.

Sean =)

2. [...] singaporeolevelmaths | Video Solution Of Plane Geometry Question (Plus:Strategy To Handle Angles) October 11th, 2008 at 7:09 pm 7 [...]

3. zhenyiing says:

I really hate geometry proof questions.
I always skipped it on papers that i tried.
Hope you could continue to provide it
Addition Mathematics is on 22 and 24 October
Really scared now.
Trembling
Thanks a lot anyway

loved
zhenyiing

4. Joscelin says:

Great! :)

So it is...
<PQT = <PRQ (alt segment theorem)
thus since
<PRQ = <PXT (corresponding <s, XT//RQ)
<PQT = <PXT
(<s in the same segment)

thanks!