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	<title>singaporeolevelmaths &#187; subsitution method</title>
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		<title>O level A-Math: 2 Different Approaches To Solve Identity Question In Factor &#8211; Remainder Theorem</title>
		<link>http://www.singaporeolevelmaths.com/2009/04/08/o-level-a-math-2-different-approaches-to-solve-identity-question-in-factor-remainder-theorem/</link>
		<comments>http://www.singaporeolevelmaths.com/2009/04/08/o-level-a-math-2-different-approaches-to-solve-identity-question-in-factor-remainder-theorem/#comments</comments>
		<pubDate>Wed, 08 Apr 2009 13:47:43 +0000</pubDate>
		<dc:creator>alwaysLovely</dc:creator>
				<category><![CDATA[A-Math]]></category>
		<category><![CDATA[Weekly Question]]></category>
		<category><![CDATA[comparing coefficients]]></category>
		<category><![CDATA[factor remainder theorem]]></category>
		<category><![CDATA[identity]]></category>
		<category><![CDATA[subsitution method]]></category>

		<guid isPermaLink="false">http://www.singaporeolevelmaths.com/?p=1271</guid>
		<description><![CDATA[In O level Additional Mathematics, there is a small section on Identity inside the topic of Factor &#38; Remainder Theorem. Today I am going to share with you the 2 different approaches to solve this kind of questions. 

Substitution Method (My preferred method)

I am going to use the question below to show you the step [...]]]></description>
			<content:encoded><![CDATA[<p>In O level Additional Mathematics, there is a small section on Identity inside the topic of Factor &amp; Remainder Theorem. Today I am going to share with you the 2 different approaches to solve this kind of questions. <strong></strong></p>
<ul>
<li><strong>Substitution Method </strong>(My preferred method)</li>
</ul>
<p>I am going to use the question below to show you the step by step solutions of both methods.</p>
<p><strong>Given that <img src="http://www.singaporeolevelmaths.com/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986.5_99bed40a06378ff02bae290c9ed5e894.png" style="vertical-align:-13.5px; display: inline-block ;" alt="3x^2+x-2=A(x-1)(x+2)+B(x-1)+C" title="3x^2+x-2=A(x-1)(x+2)+B(x-1)+C"/>  for all values of <em>x</em>, find the value of A, of B and of C.</strong></p>
<p><strong>Let <em>x</em> = 1,</strong></p>
<p><img src="http://www.singaporeolevelmaths.com/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994.5_1e082ffa7bb7e52fa67b8b86f2cc2e9d.png" style="vertical-align:-5.5px; display: inline-block ;" alt="3+1-2 = C" title="3+1-2 = C"/></p>
<p><img src="http://www.singaporeolevelmaths.com/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994.5_3088d39937d9e1c5c5c4f474acafe461.png" style="vertical-align:-5.5px; display: inline-block ;" alt="C=2" title="C=2"/></p>
<p><strong>Let <em>x</em> = -2,</strong></p>
<p><img src="http://www.singaporeolevelmaths.com/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986.5_fd6dd7a335a9f7973a7ac3d0542cc276.png" style="vertical-align:-13.5px; display: inline-block ;" alt="3(4)-2-2 = B(-3) + 2" title="3(4)-2-2 = B(-3) + 2"/></p>
<p><img src="http://www.singaporeolevelmaths.com/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986.5_fd6dd7a335a9f7973a7ac3d0542cc276.png" style="vertical-align:-13.5px; display: inline-block ;" alt="3(4)-2-2 = B(-3) + 2" title="3(4)-2-2 = B(-3) + 2"/></p>
<p><img src="http://www.singaporeolevelmaths.com/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994.5_52360cf2a70d8f38b75e175107d32d7b.png" style="vertical-align:-5.5px; display: inline-block ;" alt="B= -2" title="B= -2"/></p>
<p><strong>Let <em>x</em> = 0,</strong></p>
<p><img src="http://www.singaporeolevelmaths.com/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994.5_c45e9499ef18fece01e78429261af254.png" style="vertical-align:-5.5px; display: inline-block ;" alt="-2 = -2A+ 2 + 2" title="-2 = -2A+ 2 + 2"/></p>
<p><img src="http://www.singaporeolevelmaths.com/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994.5_ac62e0983bafc7e976fb35cd8d1883b7.png" style="vertical-align:-5.5px; display: inline-block ;" alt="A = 3" title="A = 3"/></p>
<p>Thus A = 3, B = -2 and C = 2</p>
<blockquote><p><strong>Concept behind the Subsitution method:</strong> The value of <em>x</em> choosen will cause one or more of the unknowns to be &#8220;cancel off&#8221;, leaving just 1 unknown left. For example, when I choose <em>x</em> = 1 in the first subsituition, A &amp; B are eliminated, allowing me to find &#8216;C&#8217;.</p></blockquote>
<ul>
<li><strong>Comparing Coefficients Method</strong></li>
</ul>
<p><strong>Given that <img src="http://www.singaporeolevelmaths.com/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986.5_99bed40a06378ff02bae290c9ed5e894.png" style="vertical-align:-13.5px; display: inline-block ;" alt="3x^2+x-2=A(x-1)(x+2)+B(x-1)+C" title="3x^2+x-2=A(x-1)(x+2)+B(x-1)+C"/>  for all values of <em>x</em>, find the value of A, of B and of C.</strong></p>
<p>By comparing coefficient of <img src="http://www.singaporeolevelmaths.com/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994_39f0ebcd1f89a04b5042e06d6be959ed.png" style="vertical-align:-6px; display: inline-block ;" alt="x^2" title="x^2"/>:</p>
<p>LHS: 3 = A =&gt; A = 3</p>
<p>By comparing coefficient of <img src="http://www.singaporeolevelmaths.com/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994.5_137b8dad9acade63b507e67878d3b94b.png" style="vertical-align:-5.5px; display: inline-block ;" alt="x" title="x"/>:</p>
<p>LHS: 1 = 2A &#8211; A + B =&gt; B = -2</p>
<p>By comparing coefficient of <img src="http://www.singaporeolevelmaths.com/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994_a6e9a720a2d418a7fb926a96a664aeee.png" style="vertical-align:-6px; display: inline-block ;" alt="x^0" title="x^0"/>:</p>
<p>LHS: -2 = -2A -  B + C =&gt; C = 2</p>
<p>Thus A = 3, B = -2 and C = 2</p>
<blockquote><p><strong>Concept behind the Comparing Coefficient method:</strong> Expansion is usually required on one side of the equation. It takes up time. The reason for the insignificant working shown is due to the fact that the expansion is done mentally instead of written. This method is highly recommended if there is more than 1 unknown other than <em>x </em>on the left hand side of the equation. For example, there&#8217;s an unknown &#8216;D&#8217; on the left hand side of the equation.</p></blockquote>
<p><strong>Which method do you usually use? And which method does your school teach you? Leave me your answer in the comment section below. </strong><strong>Related Articles:</strong>
<ul class="similar-posts">
<li><a href="http://www.singaporeolevelmaths.com/2008/05/15/does-stubborness-earn-you-more-marks/" rel="bookmark" title="May 15, 2008">Does Stubborness Earn You More Marks?</a></li>
</ul>
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