A-Math: Spot the Mistake in this Logarithm Equations


I gave my Secondary 4 students 1 revision question per week. The recent one I marked was on the topic of Logarithms (the fresh-killer topic for many Secondary 3).

Logarithm-error

Did you spot the error? (It's a give-away if you observe clearly)

Do this question and share your answer(s) in the comment section.

I look forward in hearing from you.

Related Post

'O' levels & Sec 3 Math & Chemistry Holiday Programmes 2010 (Revision & Headstart) UPDATE: Early Bird registration is extended to 6 Dec 09, 2359 hours (Singapore time) Credit: Art Institute of Portland Most Secondary two st...
Logarithm Equation Question 2 Solve the equation Ans : a = 1 or -6/5 Question : Do we need to include -6/5 Contributed by YC It is important for you to check if you...
O level A-Math: Fatal Mistake In Logarithm Equation You Must Aviod This is a common mistake I notice in my O level A-Math essential concepts revision workshop. Solve the following equation: First, you must i...
Logarithm Equation Question 3 This is an interesting question which I came across under Additional Mathematics (A-Math): Find the value of x. Who is courageous to work on...
Top 7 Commonly Made Mistakes in Logarithm How many of you would like to learn Math faster? And how many of you would like to score more marks for Math? Do you know that one of the fastest ...

Hi, I'm Ai Ling Ong. I enjoy coaching students who have challenges with understanding and scoring in 'O' Level A-Maths and E-Maths. I develop Math strategies, sometimes ridiculous ideas to help students in understanding abstract concepts the fast and memorable way. I write this blog to share with you the stuff I teach in my class, the common mistakes my students made, the 'way' to think, analyze... If you have found this blog post useful, please share it with your friends. I will really appreciate it! :)

6 Responses to A-Math: Spot the Mistake in this Logarithm Equations

  1. (log2(base2)8)divide by(log2(base2)x)
    is not equal to (log2(base2)8/x)

    (log2(base2)8)-(log2(base2)x)=log2(base2)8/x)

    Reply

  2. Let log2 x be y.
    2y = 3(log2 2 over log2 x) + 1
    2y - 1 = 3 ( 1 over y )
    2y^2 - y = 3
    2y^2 - y - 3 = 0
    ( 2y - 3 )( y + 1 ) = 0
    2y = 3 , y = -1
    y = 3/2

    If there is a faster method, i would like to know ;)

    Reply

Leave a reply