I gave my Secondary 4 students 1 revision question per week. The recent one I marked was on the topic of Logarithms (the fresh-killer topic for many Secondary 3).

Did you spot the error? (It's a give-away if you observe clearly)

Do this question and share your answer(s) in the comment section.

I look forward in hearing from you.

Hi, I'm Ai Ling Ong. I enjoy coaching students who have challenges with understanding and scoring in 'O' Level A-Maths and E-Maths.
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there is a wrong calculation in divition of logarithm

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(log2(base2)8)divide by(log2(base2)x)

is not equal to (log2(base2)8/x)

(log2(base2)8)-(log2(base2)x)=log2(base2)8/x)

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Let log2 x be y.

2y = 3(log2 2 over log2 x) + 1

2y - 1 = 3 ( 1 over y )

2y^2 - y = 3

2y^2 - y - 3 = 0

( 2y - 3 )( y + 1 ) = 0

2y = 3 , y = -1

y = 3/2

If there is a faster method, i would like to know ;)

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1have benefited a lot

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benefited

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