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A-Math: Spot the Mistake in this Logarithm Equations
6 Comments | Posted by alwaysLovely in A-Math
I gave my Secondary 4 students 1 revision question per week. The recent one I marked was on the topic of Logarithms (the fresh-killer topic for many Secondary 3).
Did you spot the error? (It’s a give-away if you observe clearly)
Do this question and share your answer(s) in the comment section.
I look forward in hearing from you.
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6 Comments for A-Math: Spot the Mistake in this Logarithm Equations
nirosh tharaka | March 4, 2010 at 5:53 pm
nil | March 5, 2010 at 2:05 am
(log2(base2)8)divide by(log2(base2)x)
is not equal to (log2(base2)8/x)
(log2(base2)8)-(log2(base2)x)=log2(base2)8/x)
AMath Student | March 5, 2010 at 6:15 pm
Let log2 x be y.
2y = 3(log2 2 over log2 x) + 1
2y – 1 = 3 ( 1 over y )
2y^2 – y = 3
2y^2 – y – 3 = 0
( 2y – 3 )( y + 1 ) = 0
2y = 3 , y = -1
y = 3/2
If there is a faster method, i would like to know ;)
kitty | March 8, 2010 at 4:38 pm
Hi where is this tuition centre being held? i just wanna find out whether its very far from my house:)
there is a wrong calculation in divition of logarithm
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