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	<title>Comments on: A-Math: Solving Indices Equation (Involving Common Base)</title>
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	<link>http://www.singaporeolevelmaths.com/2010/02/05/a-math-solving-indices-equation-involving-common-base/</link>
	<description>Simple Tips for Better Maths Results!</description>
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		<title>By: alake</title>
		<link>http://www.singaporeolevelmaths.com/2010/02/05/a-math-solving-indices-equation-involving-common-base/comment-page-1/#comment-2587</link>
		<dc:creator>alake</dc:creator>
		<pubDate>Mon, 03 Oct 2011 21:39:13 +0000</pubDate>
		<guid isPermaLink="false">http://www.singaporeolevelmaths.com/?p=1791#comment-2587</guid>
		<description>x5=125*squreroot of 2 pls solve d equation</description>
		<content:encoded><![CDATA[<p>x5=125*squreroot of 2 pls solve d equation</p>
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		<title>By: lpo</title>
		<link>http://www.singaporeolevelmaths.com/2010/02/05/a-math-solving-indices-equation-involving-common-base/comment-page-1/#comment-2516</link>
		<dc:creator>lpo</dc:creator>
		<pubDate>Sun, 29 May 2011 23:33:35 +0000</pubDate>
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		<description>no root exist

Possible derivation:
d/dp(4^(p-3) 7^(q-1))
 &#124; Factor out constants:
= &#124; 7^(q-1) (d/dp(4^(p-3)))
 &#124; Use the chain rule, d/dp(4^(p-3)) = ( d4^u)/( du) ( du)/( dp), where u = p-3 and ( d4^u)/( du) = 4^u log(4):
= &#124; 7^(q-1) (4^(p-3) log(4) (d/dp(p-3)))
 &#124; Differentiate the sum term by term:
= &#124; 4^(p-3) 7^(q-1) log(4) (d/dp(p)+d/dp(-3))
 &#124; The derivative of -3 is zero:
= &#124; 4^(p-3) 7^(q-1) log(4) (d/dp(p)+0)
 &#124; The derivative of p is 1:
= &#124; 1 4^(p-3) 7^(q-1) log(4)</description>
		<content:encoded><![CDATA[<p>no root exist</p>
<p>Possible derivation:<br />
d/dp(4^(p-3) 7^(q-1))<br />
 | Factor out constants:<br />
= | 7^(q-1) (d/dp(4^(p-3)))<br />
 | Use the chain rule, d/dp(4^(p-3)) = ( d4^u)/( du) ( du)/( dp), where u = p-3 and ( d4^u)/( du) = 4^u log(4):<br />
= | 7^(q-1) (4^(p-3) log(4) (d/dp(p-3)))<br />
 | Differentiate the sum term by term:<br />
= | 4^(p-3) 7^(q-1) log(4) (d/dp(p)+d/dp(-3))<br />
 | The derivative of -3 is zero:<br />
= | 4^(p-3) 7^(q-1) log(4) (d/dp(p)+0)<br />
 | The derivative of p is 1:<br />
= | 1 4^(p-3) 7^(q-1) log(4)</p>
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		<title>By: Anon</title>
		<link>http://www.singaporeolevelmaths.com/2010/02/05/a-math-solving-indices-equation-involving-common-base/comment-page-1/#comment-2457</link>
		<dc:creator>Anon</dc:creator>
		<pubDate>Fri, 01 Apr 2011 08:47:20 +0000</pubDate>
		<guid isPermaLink="false">http://www.singaporeolevelmaths.com/?p=1791#comment-2457</guid>
		<description>wow this is really helpful, thank you soo much!

can someone help me with this? please

4^p-3 * 7^q-1 ?</description>
		<content:encoded><![CDATA[<p>wow this is really helpful, thank you soo much!</p>
<p>can someone help me with this? please</p>
<p>4^p-3 * 7^q-1 ?</p>
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