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	<title>Comments on: [Video] E-Math Popular Exam Question: Finding Ratio of Areas in Vectors (Includes 3 Strategies &amp; Revision of Similar Triangles)</title>
	<atom:link href="http://www.singaporeolevelmaths.com/2009/03/27/video-e-math-popular-exam-question-finding-ratio-of-areas-in-vectors-includes-3-strategies-revision-of-similar-triangles/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.singaporeolevelmaths.com/2009/03/27/video-e-math-popular-exam-question-finding-ratio-of-areas-in-vectors-includes-3-strategies-revision-of-similar-triangles/</link>
	<description>Simple Tips for Better Maths Results!</description>
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		<title>By: alwaysLovely</title>
		<link>http://www.singaporeolevelmaths.com/2009/03/27/video-e-math-popular-exam-question-finding-ratio-of-areas-in-vectors-includes-3-strategies-revision-of-similar-triangles/comment-page-1/#comment-2169</link>
		<dc:creator>alwaysLovely</dc:creator>
		<pubDate>Mon, 20 Sep 2010 15:35:05 +0000</pubDate>
		<guid isPermaLink="false">http://www.singaporeolevelmaths.com/?p=1248#comment-2169</guid>
		<description>Are you referring to triangle BCD and ABD?
If so, if we were to consider the base of BCD to be BC, the perpendicular height is the distance between the pair of // lines BC and AD.
Similarly, if the base of triangle ABD is AD, the perpendicular height is also the distance between the pair of // lines BC and AD.

There isn&#039;t any assumption that angle DAB is a right angle.</description>
		<content:encoded><![CDATA[<p>Are you referring to triangle BCD and ABD?<br />
If so, if we were to consider the base of BCD to be BC, the perpendicular height is the distance between the pair of // lines BC and AD.<br />
Similarly, if the base of triangle ABD is AD, the perpendicular height is also the distance between the pair of // lines BC and AD.</p>
<p>There isn&#8217;t any assumption that angle DAB is a right angle.</p>
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		<title>By: alwaysLovely</title>
		<link>http://www.singaporeolevelmaths.com/2009/03/27/video-e-math-popular-exam-question-finding-ratio-of-areas-in-vectors-includes-3-strategies-revision-of-similar-triangles/comment-page-1/#comment-2168</link>
		<dc:creator>alwaysLovely</dc:creator>
		<pubDate>Mon, 20 Sep 2010 15:26:52 +0000</pubDate>
		<guid isPermaLink="false">http://www.singaporeolevelmaths.com/?p=1248#comment-2168</guid>
		<description>We need to see the diagram before deciding if the triangles are similar.
// lines don&#039;t necessarily equate to similar triangles.</description>
		<content:encoded><![CDATA[<p>We need to see the diagram before deciding if the triangles are similar.<br />
// lines don&#8217;t necessarily equate to similar triangles.</p>
]]></content:encoded>
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		<title>By: Aden</title>
		<link>http://www.singaporeolevelmaths.com/2009/03/27/video-e-math-popular-exam-question-finding-ratio-of-areas-in-vectors-includes-3-strategies-revision-of-similar-triangles/comment-page-1/#comment-2165</link>
		<dc:creator>Aden</dc:creator>
		<pubDate>Sun, 19 Sep 2010 14:24:43 +0000</pubDate>
		<guid isPermaLink="false">http://www.singaporeolevelmaths.com/?p=1248#comment-2165</guid>
		<description>Greetings! I WANT TO CLARIFY. How do we know/assume that angle DAB is a right-angle which leaves us to conclude that the height of BC is = to the height of BA? THANKS!</description>
		<content:encoded><![CDATA[<p>Greetings! I WANT TO CLARIFY. How do we know/assume that angle DAB is a right-angle which leaves us to conclude that the height of BC is = to the height of BA? THANKS!</p>
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