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Logarithm Equation Question 3
4 Comments | Posted by alwaysLovely in A-Math, Weekly Question
This is an interesting question which I came across under Additional Mathematics (A-Math):
Find the value of x.
Who is courageous to work on this question?
I will respond to this question when someone discusses about this question first :)
Update:
(Apply Power Law)
(multiply by 4 on both sides of equal sign)
(Apply Power Law)
(Apply Quotient Law)
(Factorise)
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4 Comments for Logarithm Equation Question 3
AGK | April 13, 2008 at 12:11 am
ahm97sic | November 8, 2008 at 1:06 am
This question is fun. Perhaps, you will like to let your students to try to solve the question.
Solve the equation
(2/x)^(log n 4) – (3/x)^(log n 9) = 0
Regards,
ahm97sic
ahm97sic | November 12, 2008 at 10:37 am
This is another interesting question. Perhaps, you will like to let your students to try to solve the question.
Solve (log a X)^(log b X) = X
where a, b are positive real numbers except 1, leave
the answer in terms of a and b.
Regards,
ahm97sic
















(log-baseX-root3)(log-baseX-root8)=1.5(log-baseX-1/root2)
(0.5log-baseX-3)(1.5log-baseX-2)=1.5(log-baseX-2^-0.5)
[cancel 1.5 from both sides]
(0.5log-baseX-3)(log-baseX-2)= -0.5(log-baseX-2)
[cancel 0.5 from both sides]
(log-baseX-3)(log-baseX-2) + (log-baseX-2)= 0
(log-baseX-2) (log-baseX-3 + 1) = 0
therefore,
(log-baseX-2)=0 or (log-baseX-3 + 1)=0
X^0= 2 (rejected) (log-baseX-3)= -1
X^(-1) = 3
thus X= 1/3
hope i didnt make any mistakes
Logarithm rocks! XDD
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