Logarithm Equation Question 2 [Checking validity of answers in logarithms equations]

Solve the equation

\lg(3a+2)+ lg(5a-3)=1+ 2lg (a)

Ans : a = 1 or -6/5

Question : Do we need to include -6/5

Contributed by YC

It is important for you to check if your answers are valid i.e are there any answers you would need to reject?
This is what I called checking for validity of answers.

Related Posts:

5 Responses to Logarithm Equation Question 2 [Checking validity of answers in logarithms equations]
  1. Humairah
    March 27, 2008 | 12:03 am

    I guess, we do not include -6/5 as there is no such graph of log(-a).

    Reply

  2. alwaysLovely
    March 28, 2008 | 11:09 am

    Good answer. Absolutely correct!
    Continue to participate!

    Reply

  3. Algebra
    December 5, 2008 | 2:45 pm

    Clearly the domain (admissible values of x for the argument of the function f(x)=lg(x)) of f(x) is (0, \infty). If a=-6/5, then 3a+2 is negative; therefore x=-6/5 is not admissible into the domain of function f(x).

    Reply

  4. [...] Gracious on What else do you want on this blog?nim on Be a Squaring Expert in 30 seconds!Algebra on Logarithm Equation Question 2 [Checking validity of answers in logarithms equations]alwaysLovely on Jobs galore for students this holiday seasonalwaysLovely on Jobs galore for students [...]

  5. [...] Remember to check for validity of answers. [...]

Leave a Reply

Wanting to leave an <em>phasis on your comment?

Trackback URL http://www.singaporeolevelmaths.com/2008/03/06/logarithm-equation-question-2-checking-validity-of-answers-in-logarithms-equations/trackback/