
The big thing for Sec 4 A-Math ( Oh yar, since this blog has quite a number of visitors from other countries, I think it is important for me to mention that Secondary 3 – 4 is known as Grade 9 – 10 in other countries) is CALCULUS.
Well, you will hardly find this word in your A-Math textbook but you see a bulk of the chapters dedicated to Differentiation & Integration. These 2 topics are like freezing and melting processes.
Why? Because they are simply opposite of each other !
I am going to talk about the techniques of differentiation.
There are 3 main types for Sec 4 level ; you ought to learn these techniques real well and know when to apply each one of them as application problems follow after the basics.
- Chain Rule
- Product Rule
- Quotient Rule reserved for fractions. * But some fractions can skip this rule
My personal favourite is No. 2 - Product Rule. Well, let’s see the technique in action.
Differentiate
with respect to x:
Now to do this, you can apply Product Rule – Differentiate Copy + Differentiate Copy
so 
Now from this example, we notice some patterns, if you have a constant ( a fixed number) in front, you can simply focused on differentiating the portion with x involved. For example in this case, Focus on Differentiating
so now, we don’t even have to use product rule :
- Leave the constant in front
- Differentiate the portion with x involved by Power Front – Power Down by 1-Differentiate within also known as your Chain Rule. BINGO!

By realizing this pattern, it will save you some time and less pen ink as well.
Certainly hope it is useful.
:-)
alwaysLovely
Photo by just another paul



Hi,
I'm Ai Ling. I enjoy coaching students who have challenges with
understanding and scoring in 'O' Level A-Maths and E-Maths. 

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HOW ARE TO THE FOLLOWING :
A) Y = ( X^3 – 4X )^2 ( 3 X^2 – 4 )^ 3
B) Y = ( 7x + 5 )^3 / ( 7x + 1 )
C) f(x) = 10 ( 1 – 2/x )^-2
D) f(x) = 5/(3-7x)^3
thanks.
Reply
Ai Ling Reply:
February 24th, 2011 at 12:54 am
Alvin,
I just saw your comment!
A) product rule and chain rule
B) quotient rule and chain rule
C) chain rule
D) convert qn to f(x) = 5*(3-7x)^-3; chain rule
Reply