Comments on: Application of Differentiation – Maximum/Minimum & Rate of Change http://www.singaporeolevelmaths.com/2007/09/25/application-of-differentiation-maximumminimum-rate-of-change/ Simple, Practical Tips for Better Maths Results! Tue, 07 Sep 2010 02:10:00 +0800 http://wordpress.org/?v=2.8.5 hourly 1 By: alwaysLovely http://www.singaporeolevelmaths.com/2007/09/25/application-of-differentiation-maximumminimum-rate-of-change/comment-page-1/#comment-278 alwaysLovely Mon, 14 Apr 2008 01:49:43 +0000 http://singaporeolevelmaths.com/2007/09/25/application-of-differentiation-maximumminimum-rate-of-change/#comment-278 The material for the top and bottom of the box costs $2 per square metre, and the material for the sides of the box costs $1.50 per square metre ==> Total cost for top & bottom of box = 2*2x^2 =4x^2 ==> Total cost for sides of box = 1.5*4xh =6xh ==> Total cost = 4x^2 + 6xh :) The material for the top and bottom of the box costs $2 per square metre, and the material for the sides of the box costs $1.50 per square metre

==> Total cost for top & bottom of box = 2*2x^2 =4x^2
==> Total cost for sides of box = 1.5*4xh =6xh
==> Total cost = 4x^2 + 6xh
:)

]]> By: hmm http://www.singaporeolevelmaths.com/2007/09/25/application-of-differentiation-maximumminimum-rate-of-change/comment-page-1/#comment-277 hmm Sun, 13 Apr 2008 16:54:24 +0000 http://singaporeolevelmaths.com/2007/09/25/application-of-differentiation-maximumminimum-rate-of-change/#comment-277 For Qn2, Total Cost, C =4x^2 + 6xh, Shouldn't it be C =4x^2 + 4xh instead? Maybe the question could also add in the total cost for the box For Qn2,

Total Cost, C =4x^2 + 6xh,

Shouldn’t it be C =4x^2 + 4xh instead?

Maybe the question could also add in the total cost for the box

]]> By: lijun(: http://www.singaporeolevelmaths.com/2007/09/25/application-of-differentiation-maximumminimum-rate-of-change/comment-page-1/#comment-85 lijun(: Mon, 01 Oct 2007 16:18:00 +0000 http://singaporeolevelmaths.com/2007/09/25/application-of-differentiation-maximumminimum-rate-of-change/#comment-85 i came across this qu that day, and i really want to clarify if the method i used is correct or not.<br/><br/>int(tan^2x - x^3)<br/><br/>i changed it to int(sec^2x - 1 - x^3) instead, cos i don't think we can integrate tan.<br/><br/>is that feasible? i came across this qu that day, and i really want to clarify if the method i used is correct or not.

int(tan^2x – x^3)

i changed it to int(sec^2x – 1 – x^3) instead, cos i don’t think we can integrate tan.

is that feasible?

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